If $x=(0.08)^{2}, y=frac{1}{(0.08)^{2}}$ and $z=(1-0.08)^{2}-1$, then out of the following, the true relation is

$x=(0.08)^{2}, y=frac{1}{(0.08)^{2}}=frac{10000}{64}$

$=156.25$ $quad z=(1-0.08)^{2}-1$

$=quad 1+(0.08)^{2}-2 imes 0.08-1$

$=quad(0.08)^{2}-2 imes 0.08$

$quad$ Clearly, $z