KeerthanaPosted on If x=1−2x=1-sqrt{2}x=1−2, the value of (x−1x)3left(x-frac{1}{x} ight)^{3}(x−x1)3 is a−8-8−8 b222 sqrt{2}22 c8 d1 Answer : Option CExplanation : x=1−2x=1-sqrt{2}x=1−2 ∴1x=11−2×1+21+2=−1−2 herefore frac{1}{x}=frac{1}{1-sqrt{2}} imes frac{1+sqrt{2}}{1+sqrt{2}}=-1-sqrt{2}∴x1=1−21×1+21+2=−1−2 ∴(x−1x)3=(1−2+1+2)3=23=8 hereforeleft(x-frac{1}{x} ight)^{3}=(1-sqrt{2}+1+sqrt{2})^{3}=2^{3}=8∴(x−x1)3=(1−2+1+2)3=23=8 Rate This:NaN / 5 - 1 votesAdd comment