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If x+1x=99x+frac{1}{x}=99, find the value of 100x2x2+102x+2frac{100 x}{2 x^{2}+102 x+2}

a

16frac{1}{6}

b

12frac{1}{2}

c

13frac{1}{3}

d

14frac{1}{4}

Answer : Option C
Explanation :

x+1x=99x+frac{1}{x}=99

100x2x2+102x+2=100x2x2+2+102x herefore frac{100 x}{2 x^{2}+102 x+2}=frac{100 x}{2 x^{2}+2+102 x}

x . से भाग देने पर

=1002x+2x+102=1002(x+1x)+102=frac{100}{2 x+frac{2}{x}+102}=frac{100}{2left(x+frac{1}{x} ight)+102}

=1002×99+102=100300=13=frac{100}{2 imes 99+102}=frac{100}{300}=frac{1}{3}

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