KeerthanaPosted on If x+1x=99x+frac{1}{x}=99x+x1=99, find the value of 100x2x2+102x+2frac{100 x}{2 x^{2}+102 x+2}2x2+102x+2100x a16frac{1}{6}61 b12frac{1}{2}21 c13frac{1}{3}31 d14frac{1}{4}41 Answer : Option CExplanation : x+1x=99x+frac{1}{x}=99x+x1=99 ∴100x2x2+102x+2=100x2x2+2+102x herefore frac{100 x}{2 x^{2}+102 x+2}=frac{100 x}{2 x^{2}+2+102 x}∴2x2+102x+2100x=2x2+2+102x100x x . से भाग देने पर =1002x+2x+102=1002(x+1x)+102=frac{100}{2 x+frac{2}{x}+102}=frac{100}{2left(x+frac{1}{x} ight)+102}=2x+x2+102100=2(x+x1)+102100 =1002×99+102=100300=13=frac{100}{2 imes 99+102}=frac{100}{300}=frac{1}{3}=2×99+102100=300100=31 Rate This:NaN / 5 - 1 votesAdd comment