If $x^{4}+frac{1}{x^{4}}=23$, then the value of $left(x-frac{1}{x} ight)^{2}$ will be

$x^{4}+frac{1}{x^{4}}=23$

$Rightarrowleft(x^{2}+frac{1}{x^{2}} ight)^{2}-2=23$

$Rightarrowleft(x^{2}+frac{1}{x^{2}} ight)^{2}=23+2=25$

$herefore quad x^{2}+frac{1}{x^{2}}=5$

$herefore quadleft(x-frac{1}{x} ight)^{2}=x^{2}+frac{1}{x^{2}}-2$

$quad=5-2=3$