A tent is to be built in the form of a cylinder of radius 10 metre surmounted by a cone of the same radius. If the height of the cylindrical part is 5 metre and slant height of the conical part is 15 metre, how much canvas will be required to build the tent? Allow 20% extra canvas for folding and stitching. $left( ight.$ Take $left.pi=frac{22}{7} ight)$

Curved surface area of cylindrical part = 2Srh

$=2 imes frac{22}{7} imes 10 imes 5=frac{2200}{7}$ sq. metre

Curved surface area of conical part = πrl

$=frac{22}{7} imes 10 imes 15=frac{3300}{7}$ sq. metre

Total curved surface area

$=left(frac{2200}{7}+frac{3300}{7} ight)$ sq. metre $=frac{5500}{7}$ sq. metre

∴ Area of required canvas

$=left(frac{5500}{7} imes frac{120}{100} ight)$ sq. metre $=942.85$ sq. metre