minutes and 3 hours 20 minutes to reach Y and X respectively after they meet. If train A is moving at 45 km/hr., then the speed of the train B is

$frac{{{S_2}}}{{{S_1}}} = sqrt {frac{{frac{{24}}{5}}}{{frac{{10}}{3}}}} = sqrt {frac{{72}}{{50}}}$

$frac{{{S_2}}}{{{S_1}}} = sqrt {frac{{36}}{{25}}} = frac{6}{5}$

${S_2} = frac{{45 imes 6}}{5}$

$= 54frac{{{ m{km}}}}{{{ m{hr}}}}$