Satish start from A and walks 2 km east upto B and turns southwards and walks 1 km upto C. At C he turns to east and walks 2 km upto D. He then turns northwards and walks 4 km to E. How far is he from his starting point ?

Answer : Option A

Explanation :

Required distance $\mathrm{AE}=\sqrt{(\mathrm{AF})^{2}+(\mathrm{EF})^{2}}$

$=\sqrt{(4)^{2}+(3)^{2}}=\sqrt{16+9}=\sqrt{25}=5 \mathrm{~km}$