KeerthanaPosted on tan 56° का मूल्य क्या होता है? asin11∘−cos11∘cos11∘+sin11∘frac{sin 11^{circ}-cos 11^{circ}}{cos 11^{circ}+sin 11^{circ}}cos11∘+sin11∘sin11∘−cos11∘ bcos11∘+sin11∘sin11∘−cos11∘frac{cos 11^{circ}+sin 11^{circ}}{sin 11^{circ}-cos 11^{circ}}sin11∘−cos11∘cos11∘+sin11∘ ccos11∘−sin11∘cos11∘+sin11∘frac{cos 11^{circ}-sin 11^{circ}}{cos 11^{circ}+sin 11^{circ}}cos11∘+sin11∘cos11∘−sin11∘ dcos11∘+sin11∘cos11∘−sin11∘frac{cos 11^{circ}+sin 11^{circ}}{cos 11^{circ}-sin 11^{circ}}cos11∘−sin11∘cos11∘+sin11∘ Answer : Option DExplanation : tan 56° = tan(45° + 11°) =tan45∘+tan11∘1−tan45∘⋅tan11∘=frac{ an 45^{circ}+ an 11^{circ}}{1- an 45^{circ} cdot an 11^{circ}}=1−tan45∘⋅tan11∘tan45∘+tan11∘ ∵tan(A+B)=tanA+tanB1−tanAtanBecause an (mathrm{A}+mathrm{B})=frac{ an mathrm{A}+ an mathrm{B}}{1- an mathrm{A} an mathrm{B}}∵tan(A+B)=1−tanAtanBtanA+tanB ∵tan45∘=1ecause an 45^{circ}=1∵tan45∘=1 =1+tan11∘1−tan11∘=1+sin11∘cos11∘1−sin11∘cos11∘=cos11∘+sin11∘cos11∘−sin11∘=frac{1+ an 11^{circ}}{1- an 11^{circ}}=frac{1+frac{sin 11^{circ}}{cos 11^{circ}}}{1-frac{sin 11^{circ}}{cos 11^{circ}}}=frac{cos 11^{circ}+sin 11^{circ}}{cos 11^{circ}-sin 11^{circ}}=1−tan11∘1+tan11∘=1−cos11∘sin11∘1+cos11∘sin11∘=cos11∘−sin11∘cos11∘+sin11∘ Rate This:NaN / 5 - 1 votesAdd comment
