KeerthanaPosted on tan(π4+x) an left(frac{pi}{4}+x ight)tan(4π+x) का मूल्य क्या है? a1+tanx1−tanxfrac{1+ an x}{1- an x}1−tanx1+tanx b1−tanx1+tanxfrac{1- an x}{1+ an x}1+tanx1−tanx c1+cotx1−cotxfrac{1+cot x}{1-cot x}1−cotx1+cotx d1−cotx1+cotxfrac{1-cot x}{1+cot x}1+cotx1−cotx Answer : Option AExplanation : tan(π4+x)=tanπ4+tanx1−tanπ4⋅tanx an left(frac{pi}{4}+x ight)=frac{ an frac{pi}{4}+ an x}{1- an frac{pi}{4} cdot an x}tan(4π+x)=1−tan4π⋅tanxtan4π+tanx [∵tan(A+B)=tanA+tanB1−tanAtanB]left[ecause an (A+B)=frac{ an A+operatorname{tanB}}{1- an A an B} ight][∵tan(A+B)=1−tanAtanBtanA+tanB] =1+tanx1−tanx=frac{1+ an x}{1- an x}=1−tanx1+tanx Rate This:NaN / 5 - 1 votesAdd comment
