The aggregate pass percentage during the three years was

$82 frac{44}{113} \%$

$82 frac{55}{113} \%$

$80 frac{60}{113} \%$

$77 frac{29}{113} \%$

Answer : Option C

Explanation :

Total passed students,

= 140 + 150 + 165 = 455

Total students =170 + 195 + 200 = 565

$herefore$ Required percentage $=frac{455}{565} imes 100$

$=frac{9100}{113}=80 frac{60}{113} \%$