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The area bounded by the lines x = 0, y = 0, x + y = 1, 2x + 3y = 6 (in square units) is

a

2

b

2132 \frac{1}{3}

c

2122 \frac{1}{2}

d

3

Answer : Option C
Explanation :

x = 0 is the equation of y-axis.

y = 0 is the equation of x-axis.

Putting x = 0 in x + y =1, y = 1

Putting y = 0 in x + y =1, x = 1

Putting x = 0 in 2x + 3y = 6

3y = 6 ⇒ y = 2

Putting y = 0 in 2x + 3y = 6

2x = 6 ⇒ x = 3

∴ OB = 1; OA = 1

∴ Required area = ΔOCD – ΔOAB

=12×3×212×1×1=312=212=\frac{1}{2} \times 3 \times 2-\frac{1}{2} \times 1 \times 1=3-\frac{1}{2}=2 \frac{1}{2} sq. units

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