KeerthanaPosted on The distance between the lines y=mx+c1y=m x+c_{1}y=mx+c1 and yyy =mx+c2=m x+c_{2}=mx+c2 is ac1−c2m2+1\frac{c_{1}-c_{2}}{\sqrt{m^{2}+1}}m2+1c1−c2 b∣c1−c21+m2∣\left|\frac{c_{1}-c_{2}}{\sqrt{1+m^{2}}}\right|∣∣1+m2c1−c2∣∣ cc2−c11+m2\frac{c_{2}-c_{1}}{\sqrt{1+m^{2}}}1+m2c2−c1 d0 Answer : Option BExplanation : Let the distance between the lines be d ⇒d=∣y−mx−c11+m2∣\Rightarrow d=\left|\frac{y-m x-c_{1}}{\sqrt{1+m^{2}}}\right|⇒d=∣∣1+m2y−mx−c1∣∣ Also we know that y−mx=c2y-m x=c_{2}y−mx=c2 ⇒d=∣c2−c11+m2∣\Rightarrow d=\left|\frac{c_{2}-c_{1}}{\sqrt{1+m^{2}}}\right|⇒d=∣∣1+m2c2−c1∣∣ =∣c1−c21+m2∣=\left|\frac{c_{1}-c_{2}}{\sqrt{1+m^{2}}}\right|=∣∣1+m2c1−c2∣∣ Rate This:NaN / 5 - 1 votesAdd comment