The distance of the point (3, – 1) from the line12x – 5y – 7 = 0 will be ?

Let required distance = d

$Rightarrow d_{(3,-1)}=left|frac{12 x-5 y-7}{sqrt{12^{2}+5^{2}}} ight|$

$=left|frac{12 imes 3-5 imes-1-7}{sqrt{169}} ight|$

$=left|frac{36+5-7}{13} ight|=left|frac{34}{13} ight|=frac{34}{13}$ units