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The graphs of 2x + 1 = 0 and 3y – 9 = 0 intersect at the point 2x + 1 = 0

a

$left(-frac{1}{2}, 3 ight)$

b

$left(-frac{1}{2},-3 ight)$

c

$left(frac{1}{2},-3 ight)$

d

None of these

Answer : Option A

Explanation :

$2 x+1=0 Rightarrow x=-frac{1}{2}$

and 3y – 9 = 0 ⇒ y = 3