Keerthana
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The numerical value of 11+cot2θ+31+tan2θ+2sin2θfrac{1}{1+cot ^{2} heta}+frac{3}{1+ an ^{2} heta}+2 sin ^{2} heta will be

a

6

b

2

c

5

d

3

Answer : Option D
Explanation :

11+cot2θ+31+tan2θ+2sin2θfrac{1}{1+cot ^{2} heta}+frac{3}{1+ an ^{2} heta}+2 sin ^{2} heta

=1cosec2θ+3sec2θ+2sin2θ=frac{1}{operatorname{cosec}^{2} heta}+frac{3}{sec ^{2} heta}+2 sin ^{2} heta

=sin2θ+3cos2θ+2sin2θ=sin ^{2} heta+3 cos ^{2} heta+2 sin ^{2} heta

=3(sin2θ+cos2θ)=3=3left(sin ^{2} heta+cos ^{2} heta ight)=3

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