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Keerthana
Posted on

The percentage of metals in a mine of lead ore is 60%60 \%. Now the percentage of silver is 34%\frac{3}{4} \% of metals and the rest is lead. If the mass of ore extracted from this mine is 8000 kg8000 \mathrm{~kg}, the mass (in kg.) of lead is :

a

4763

b

4762

c

4764

d

4761

Answer : Option C
Explanation :

Required mass of lead =8000×60100×=8000 \times \frac{60}{100} \times

(1−3400)\left(1-\frac{3}{400}\right)

=8000×60100×397400=4764 kg=8000 \times \frac{60}{100} \times \frac{397}{400}=4764 \mathrm{~kg}

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