KeerthanaPosted on The percentage of students passed in 1st division in 1982 was 1982 a1427%14 frac{2}{7} \%1472% b111317%11 frac{13}{17} \%111713% c20%20 \%20% d34%34 \%34% Answer : Option BExplanation : Required percentage =20170×100=20017=111317%=frac{20}{170} imes 100=frac{200}{17}=11 frac{13}{17} \%=17020×100=17200=111713% Rate This:NaN / 5 - 1 votesAdd comment