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The ratio of alcohol and water in 40 litres of mixture is 5 : 3. Then 8 litres of the mixture is removed and replaced with water. Now, the ratio of the alcohol and water in the resultant mixture is

a

1 : 2

b

1 : 3

c

1 : 1

d

2 : 1

Answer : Option C

Explanation :

In 32 litres of mixture

Alcohol $=frac{5}{8} imes 32=20$ litre

Water $=frac{3}{8} imes 32=12$ litre

$herefore$ Required ratio $=20: 20=1: 1$