The simplified form of $frac{112 b^{3} x^{2} a^{4} z^{3}}{7 a^{3} b^{2} z}$

$frac{112 b^{3} x^{2} a^{4} z^{3}}{7 a^{3} b^{2} z}=left(frac{112}{7} ight)left(frac{b^{3}}{b^{2}} ight) x^{2} cdotleft(frac{a^{4}}{a^{3}} ight)left(frac{z^{3}}{z} ight)$

= 16bx²az²