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The value of k, for which the system of equations 3x – ky – 20 = 0 and 6x – 10y + 40 = 0 has no solution,

a

3

b

5

c

6

d

10

Answer : Option B
Explanation :

System of equations

a1x+b1y+c1=0a_{1} x+b_{1} y+c_{1}=0 and a2x+b2y+c2=0a_{2} x+b_{2} y+c_{2}=0 will have no solution if

a1a2=b1b2c1c2frac{a_{1}}{a_{2}}=frac{b_{1}}{b_{2}} eq frac{c_{1}}{c_{2}}

36=k102040 herefore frac{3}{6}=frac{-k}{-10} eq frac{-20}{40}

12=k10k=102=5Rightarrow frac{1}{2}=frac{k}{10} Rightarrow k=frac{10}{2}=5

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