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The value of tan1°tan2° tan3°....... tan89° is : tan 1° tan 2° tan 3° ...... tan 89°

a

0

b

1

c

3sqrt{3}

d

13frac{1}{sqrt{3}}

Answer : Option B
Explanation :

tan1°.tan2°.tan3°... tan45°... tan88°tan89°

= (tan1°.tan89°) (tan2°. tan88°) ... tan45°

= (tan1°.cot1°).(tan2°.cot2°) ... tan45° = 1

[tan(90θ)=cotθ,tanθcotθ=1]left[ecause an left(90^{circ}- heta ight)=cot heta, an heta cdot cot heta=1 ight]

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