KeerthanaPosted on Books read by A & D together in 2005 are what percent more than books read by C in 2006? a 4623%46frac{2}{3}{ m{\% }}4632% b 5413%54frac{1}{3}{ m{\% }}5431% c 2523%25frac{2}{3}{ m{\% }}2532% d 3313%33frac{1}{3}{ m{\% }}3331% e 6623%66frac{2}{3}{ m{\% }}6632% Answer : Option EExplanation : Required % = {(72+48)−72}72×100frac{{left{ {left( {72 + 48} ight) - 72} ight}}}{{72}} imes 10072{(72+48)−72}×100 =2003%=6623% = frac{{200}}{3}{ m{\% }} = 66frac{2}{3}{ m{\% }}=3200%=6632% Rate This:5.0 / 5 - 1 votesAdd comment