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Two line segments PQ and RS intersect at X in such a way that XP = XR. If ∠PSX = ∠RQX, then one must have

a

ar(ΔPXR) = ar(ΔQXS)

b

PS = RQ

c

∠XSQ = ∠XRP

d

PR = QS

Answer : Option B

Explanation :

XP = XR

∴ ∠XPR = ∠XRP

If ∠PSX = ∠RQX,

then, PS = RQ