Two trains of equal length are running on parallel lines in the same direction at 46 km/hour and 36 km/hour. The faster train passes the slower train in 36 seconds. The length of each train is

Let the length of each train be x metre.

Relative speed = (46 – 36) kmph

$=10 \mathrm{kmph}=\left(\frac{10 \times 5}{18}\right) \mathrm{m} . / \mathrm{sec} .=\frac{25}{9} \mathrm{~m} . / \mathrm{sec} .$

$\therefore \frac{2 x}{\frac{25}{9}}=36$

$\therefore 2 x=36 \times \frac{25}{9}=100$

$\Rightarrow x=\frac{100}{2}=50$ metre