Keerthana
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What is the average of students who participating in Play from all class.

a

321232frac{1}{2}

b

341234frac{1}{2}

c

271227frac{1}{2}

d

351235frac{1}{2}

e

301230frac{1}{2}

Answer : Option A
Explanation :

Required average

= 8100×500+6100×400+10100×360+12100×2504frac{{frac{8}{{100}} imes 500 + frac{6}{{100}} imes 400 + frac{{10}}{{100}} imes 360 + frac{{12}}{{100}} imes 250}}{4}

=1304=652=3212 = frac{{130}}{4} = frac{{65}}{2} = 32frac{1}{2}

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