KeerthanaPosted on What is the correct order of averages of the given players in the four matches? aA > E > B > C > D bE > A > C > D > B cA > E > C > D > B dE > A > D > C > B Answer : Option AExplanation : Average Runs: A⇒70+105+55+1354=3654mathrm{A} Rightarrow frac{70+105+55+135}{4}=frac{365}{4}A⇒470+105+55+135=4365 B⇒40+35+95+724=2424mathrm{~B} Rightarrow frac{40+35+95+72}{4}=frac{242}{4} B⇒440+35+95+72=4242 C⇒60+68+75+854=2884mathrm{C} Rightarrow frac{60+68+75+85}{4}=frac{288}{4}C⇒460+68+75+85=4288 D⇒95+45+55+604=2554mathrm{D} Rightarrow frac{95+45+55+60}{4}=frac{255}{4}D⇒495+45+55+60=4255 E⇒105+110+125+1224=4624mathrm{E} Rightarrow frac{105+110+125+122}{4}=frac{462}{4}E⇒4105+110+125+122=4462 Clearly, E > A > C > D > B Rate This:NaN / 5 - 1 votesAdd comment