KeerthanaPosted on What is the distance of the point (2, 3) from the line 2x + 3y + 4 = 0 ? a1513\frac{15}{\sqrt{13}}1315 b1613\frac{16}{\sqrt{13}}1316 c1713\frac{17}{\sqrt{13}}1317 d813\frac{8}{\sqrt{13}}138 Answer : Option CExplanation : Let the distance be d ⇒d=∣2x+3y+422+32∣\Rightarrow d=\left|\frac{2 x+3 y+4}{\sqrt{2^{2}+3^{2}}}\right|⇒d=∣∣22+322x+3y+4∣∣ d(2,3)=∣2×2+3×3+413∣d_{(2,3)}=\left|\frac{2 \times 2+3 \times 3+4}{\sqrt{13}}\right|d(2,3)=∣∣132×2+3×3+4∣∣ d(2,3)=∣1713∣d_{(2,3)}=\left|\frac{17}{\sqrt{13}}\right|d(2,3)=∣∣1317∣∣ ⇒d(2,3)=1713\Rightarrow d_{(2,3)}=\frac{17}{\sqrt{13}}⇒d(2,3)=1317 units Rate This:NaN / 5 - 1 votesAdd comment