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What is the equation of a line perpendicular to the line x – 7y + 5 = 0 and having x-intercept 3?

a

x + 7y = 21

b

7x + y = 21

c

x + 2y = 10

d

–x + y = 15

Answer : Option B
Explanation :

Let the slope of line be m

Here,

m1=17=17m_{1}=\frac{-1}{-7}=\frac{1}{7}

As lines are perpendicular,

m1×m2=1\therefore m_{1} \times m_{2}=-1

m×17=1m \times \frac{1}{7}=-1

m=7m=-7

\therefore Equation of line is

(yy1)=m(xx1)\left(y-y_{1}\right)=m\left(x-x_{1}\right)

(y0)=7(x3)(y-0)=-7(x-3)

y=7x+21y=-7 x+21

7x+y=21\Rightarrow 7 x+y=21

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