KeerthanaPosted on What is the equation of the line if its slope is 34frac{3}{4}43 and yyy-intercept is 5?5 ?5? a3x + 4y = 20 b3x – 4y = 20 c3x + 4y = – 20 d3x – 4y = – 20 Answer : Option DExplanation : The required equation is : y = mx + c where m=34m=frac{3}{4}m=43 and c=5c=5c=5 ∴y=34x+5 herefore y=frac{3}{4} x+5∴y=43x+5 ⇒4y=3x+20Rightarrow 4 y=3 x+20⇒4y=3x+20 ⇒3x−4y=−20Rightarrow 3 x-4 y=-20⇒3x−4y=−20 Rate This:NaN / 5 - 1 votesAdd comment