KeerthanaPosted on What is the value of positive square root of (69+(69+(69+ 28528 sqrt{5}285 )? a2−752-7 sqrt{5}2−75 b7−257-2 sqrt{5}7−25 c7+257+2 sqrt{5}7+25 d2+752+7 sqrt{5}2+75 Answer : Option CExplanation : 69+285=69+2×7×2569+28 sqrt{5}=69+2 imes 7 imes 2 sqrt{5}69+285=69+2×7×25 =49+20+2×7×25=49+20+2 imes 7 imes 2 sqrt{5}=49+20+2×7×25 =(7)2+(25)2+2×7×25=(7+25)2=(7)^{2}+(2 sqrt{5})^{2}+2 imes 7 imes 2 sqrt{5}=(7+2 sqrt{5})^{2}=(7)2+(25)2+2×7×25=(7+25)2 ∴69+285=(7+25)2=7+25 herefore sqrt{69+28 sqrt{5}}=sqrt{(7+2 sqrt{5})^{2}}=7+2 sqrt{5}∴69+285=(7+25)2=7+25 Rate This:NaN / 5 - 1 votesAdd comment