KeerthanaPosted on What will be the equation of a line passing through the point (–4, 3) and having slope 12\frac{1}{2}21 ? ax – 2y + 5 = 0 b–x + 2y + 10 = 0 cx – 2y + 6 = 0 dx – 2y + 10 = 0 Answer : Option DExplanation : Let the equation of line be y−y1=m(x−x1)y-y_{1}=m\left(x-x_{1}\right)y−y1=m(x−x1) Here, m=12m=\frac{1}{2}m=21 and x1=−4,y1=3x_{1}=-4, y_{1}=3x1=−4,y1=3 ⇒\Rightarrow⇒ Equation of line be y−3=12(x+4)y-3=\frac{1}{2}(x+4)y−3=21(x+4) 2y−6=x+42 y-6=x+42y−6=x+4 x−2y+10=0x-2 y+10=0x−2y+10=0 Rate This:NaN / 5 - 1 votesAdd comment