Keerthana
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(i) 21x² + 10x + 1 = 0

(ii) 24y²+ 26y + 5 = 0

a

x ≤ y

b

x = y or no relation can be established between x & y.

c

x ≥ y

d

x > y

e

x < y

Answer : Option B
Explanation :

21x2+10x+1=021{x^2} + 10x + 1 = 0

21x2+7x+3x+1=021{x^2} + 7x + 3x + 1 = 0

7x(3x+1)+1(3x+1)=07xleft( {3x + 1} ight) + 1left( {3x + 1} ight) = 0

x=13,17x = frac{{ - 1}}{3},frac{{ - 1}}{7}

24y2+26y+5=024{y^2} + 26y + 5 = 0

24y2+(20+6)y+5=024{y^2} + left( {20 + 6} ight)y + 5 = 0

24y2+20y+6y+5=024{y^2} + 20y + 6y + 5 = 0

4y(6y+5)+1(6y+5)=04yleft( {6y + 5} ight) + 1left( {6y + 5} ight) = 0

y=56,14y = frac{{ - 5}}{6}, - frac{1}{4}

No relation between x and y

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