KeerthanaPosted on (i) 21x² + 10x + 1 = 0 (ii) 24y²+ 26y + 5 = 0 a x ≤ y b x = y or no relation can be established between x & y. c x ≥ y d x > y e x < y Answer : Option BExplanation : 21x2+10x+1=021{x^2} + 10x + 1 = 021x2+10x+1=0 21x2+7x+3x+1=021{x^2} + 7x + 3x + 1 = 021x2+7x+3x+1=0 7x(3x+1)+1(3x+1)=07xleft( {3x + 1} ight) + 1left( {3x + 1} ight) = 07x(3x+1)+1(3x+1)=0 x=−13,−17x = frac{{ - 1}}{3},frac{{ - 1}}{7}x=3−1,7−1 24y2+26y+5=024{y^2} + 26y + 5 = 024y2+26y+5=0 24y2+(20+6)y+5=024{y^2} + left( {20 + 6} ight)y + 5 = 024y2+(20+6)y+5=0 24y2+20y+6y+5=024{y^2} + 20y + 6y + 5 = 024y2+20y+6y+5=0 4y(6y+5)+1(6y+5)=04yleft( {6y + 5} ight) + 1left( {6y + 5} ight) = 04y(6y+5)+1(6y+5)=0 y=−56,−14y = frac{{ - 5}}{6}, - frac{1}{4}y=6−5,−41 No relation between x and y Rate This:NaN / 5 - 1 votesAdd comment